A) Equal to 0.1 m
B) Between 0.1 and 0.2
C) Equal to 0.2 m
D) More than 0.2 m
Correct Answer: D
Solution :
\[W(h+\delta )=\frac{1}{2}k{{\delta }^{2}}\] \[100(2+\delta )=\frac{1}{2}\times 1000\times {{\delta }^{2}}\] \[=5{{\delta }^{2}}-\delta -2=0\] \[\delta =\frac{1\pm \sqrt{1+40}}{10}=0.74\,m>0.2\,m\]You need to login to perform this action.
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