A) 1-butanol
B) 2-butanol
C) 3-butanol
D) 4-heptanol
Correct Answer: B
Solution :
2-butanol \[(C{{H}_{3}}-\underset{OH}{\mathop{\underset{|\,\,\,\,\,\,}{\mathop{CH}}\,}}\,-C{{H}_{2}}-C{{H}_{3}})\] is optically active because it has asymmetric carbon atom.You need to login to perform this action.
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