A) 1
B) 2
C) 3
D) 4
Correct Answer: B
Solution :
Only one chiral centre. Hence two optical isomers are possible. No. of optical isomer = \[{{2}^{n}}\] (where n = no. of chiral carbon) = \[{{2}^{1}}\] = 2.You need to login to perform this action.
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