JEE Main & Advanced Chemistry GOC Question Bank Structural and stereo isomerism

  • question_answer The number of enantiomers of the compound \[C{{H}_{3}}CHBrCHBrCOOH\] is [AIIMS 1997]

    A) 0

    B) 1

    C) 3

    D) 4

    Correct Answer: D

    Solution :

      \[C{{H}_{3}}-\underset{Br\,}{\mathop{\underset{|\,\,\,\,}{\overset{\overset{H}{\mathop{|\,\,}}\,}{\mathop{{{C}_{*}}}}}\,}}\,-\underset{Br\,}{\overset{H}{\mathop{\underset{|\,\,\,}{\overset{|\,\,}{\mathop{{{C}_{*}}}}}\,}}}\,-COOH\] Number of enantiomers = \[{{2}^{n}}\] (n = asymmetric Carbon atom) = \[{{2}^{2}}\] = 4.

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