A) \[HC\equiv C-\underset{Cl\,}{\overset{H\,}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,-}}}\,C\equiv CH\]
B) \[HC\equiv C-\underset{Cl}{\overset{H}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-C{{H}_{3}}\]
C) \[HC\equiv C-\underset{Cl}{\overset{H}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-H\]
D) \[HC\equiv C-\overset{Cl}{\mathop{\overset{|}{\mathop{C}}\,}}\,=C{{H}_{2}}\]
Correct Answer: B
Solution :
\[HC\equiv C-\underset{Cl\ }{\mathop{\overset{H}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}\,-}}\,C{{H}_{3}}\] shows optical isomerism because of molecule is unsymmetrical. That is called chiral.You need to login to perform this action.
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