A) \[_{56}^{99}Ba\]
B) \[_{56}^{43}Ba\]
C) \[_{43}^{99}Tc\]
D) \[_{43}^{56}Tc\]
Correct Answer: C
Solution :
Given mass number (Z) = 99 no. of neutrons =56 \[\therefore \] no. of protons = atomic number = 99 - 56 = 43 i.e. \[_{43}T{{C}^{99}}\]You need to login to perform this action.
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