A) \[{{D}^{+}}\]
B) \[{{H}^{+}}\]
C) \[He\]
D) \[L{{i}^{+}}\]
Correct Answer: A
Solution :
\[_{1}^{2}D\] has \[1\] electron, \[1\] proton and \[1\] neutron, This on ionisation, lost its only one electron and got converted to V. Therefore, \[D+\] has only \[1\] proton and \[1\] neutron.You need to login to perform this action.
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