A) \[27:13\]
B) \[10:13\]
C) \[20:24\]
D) \[10:14\]
Correct Answer: B
Solution :
Let the neutral atom of the element be X. Given, the nuclear charge of \[X\] is \[13\] times that of hydrogen nucleus. \[\Rightarrow \]Atomic number\[=13\] Mass of \[X\] is \[27\] times that of hydrogen nucleus \[\Rightarrow \]Mass number\[=27\]. Since\[_{13}^{27}X,\,\,EC=2,\,\,8,\,\,3\] If \[X\] forms a stable, positively charged ion, i.e. \[{{X}^{+3}}\](as it has \[3\] valence electrons in its valence shell) \[{{X}^{+3}}\to \]Atomic number\[=13-3=10\].This implies that the number of electrons\[=10\]. Number of protons\[=13\]. Ratio\[=10:13\]or\[20:26\].You need to login to perform this action.
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