JEE Main & Advanced Mathematics Definite Integration Question Bank Summation of series by Definite Integration, Gamma function, Leibnitz's rule

  • question_answer
    \[\int_{\,-\pi /2}^{\,\pi /2}{{{\sin }^{4}}x{{\cos }^{6}}x\,dx=}\]                                    [EAMCET 2002]

    A)                 \[\frac{3\pi }{64}\]          

    B)                 \[\frac{3\pi }{572}\]

    C)                 \[\frac{3\pi }{256}\]       

    D)                 \[\frac{3\pi }{128}\]

    Correct Answer: C

    Solution :

                       \[I=\int_{-\pi /2}^{\pi /2}{{{\sin }^{4}}x{{\cos }^{6}}x\,dx}\]\[=2\int_{0}^{^{\pi /2}}{{{\sin }^{4}}x\,{{\cos }^{6}}x.\,dx}\]            \[\begin{matrix}    \because \int_{-a}^{a}{f(x)\,dx=2\int_{0}^{a}{f(x)\,dx,}} & \text{if }f(-x)=f(x)  \\    \,\,\,\,\,=0, & \text{if }f(-x)=-f(x)  \\ \end{matrix}\]             Applying Gamma function, we get \[I=\frac{2\,\Gamma 5/2\,.\,\Gamma 7/2}{2\,.\Gamma 6}\]                                 \[=\frac{3/2.1/2.\sqrt{\pi .}5/2.3/2.1/2.\sqrt{\pi }}{5.4.3.2.1}\]\[=\frac{3\pi }{{{2}^{8}}}=\frac{3\pi }{256}\].


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