A) \[\cos x+x\sin x\]
B) \[x\sin x\]
C) \[x\cos x\]
D) None of these
Correct Answer: B
Solution :
Since,\[f(x)=\int_{0}^{x}{t\sin tdt}\].Now, according to Leibnitz's rule, \[{f}'(x)=x\,\sin x.(1)-0=x\sin x\].You need to login to perform this action.
You will be redirected in
3 sec