A) A circle
B) An ellipse
C) A straight line
D) A parabola
Correct Answer: C
Solution :
If \[{{y}_{1}}={{a}_{1}}\sin \omega \,t\] and \[{{y}_{2}}={{a}_{2}}\sin (\omega \,t+0)={{a}_{2}}\sin \omega \,t\] Þ \[\frac{y_{1}^{2}}{a_{1}^{2}}+\frac{y_{2}^{2}}{a_{2}^{2}}-\frac{2{{y}_{1}}{{y}_{2}}}{{{a}_{1}}{{a}_{2}}}=0\]Þ \[{{y}_{2}}=\frac{{{a}_{2}}}{{{a}_{1}}}{{y}_{1}}\]
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