A) 8cm
B) 10cm
C) 12cm
D) 14cm
Correct Answer: B
Solution :
Given that the length of the longest rod = 27 cm Length of the box, \[l=\text{23 cm}\] Breadth of the box, b = 10 cm Let 'h' be the height of the box Length of the longest rod = Length of the diagonal\[=\sqrt{{{l}^{2}}+{{b}^{2}}+{{h}^{2}}}\] \[\Rightarrow \]\[27=\sqrt{{{(23)}^{2}}+{{(10)}^{2}}+{{h}^{2}}}\] Squaring on both sides \[\Rightarrow \]\[{{(27)}^{2}}={{(23)}^{2}}+{{(10)}^{2}}+{{h}^{2}}\] \[\Rightarrow \]\[h=\sqrt{100}=10\,cm\] Hence, the height of the box = 10 cmYou need to login to perform this action.
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