9th Class Mathematics Surface Areas and Volumes Question Bank Surface Areas and Volumes

  • question_answer
    A metal sheet 27 cm long, 8 cm broad and 1 cm thick is melted into a cube. Find the difference between surface areas of two solids.

    A) \[~280\text{ }c{{m}^{2}}\]      

    B)                    \[~284\text{ }c{{m}^{2}}\]     

    C)        \[~296\text{ }c{{m}^{2}}\]                 

    D)        \[286\text{ }c{{m}^{2}}\]

    Correct Answer: D

    Solution :

    Volume of the metal sheet \[(27\times 8\times 1)c{{m}^{3}}=216\,c{{m}^{3}}\] Surface area of the metal sheet \[=(27\times 8+8\times 1+1\times 27)\] \[=2(216+8+27)=502\,c{{m}^{2}}\] Volume of cube = Volume of metal sheet \[{{(side)}^{2}}=216\,c{{m}^{3}}\Rightarrow side=6\,cm\] Now, surface area of cube\[=6{{(6)}^{2}}=216\,c{{m}^{2}}\] \[\therefore \]Required difference\[=(520-216)c{{m}^{2}}\] \[=286\,c{{m}^{2}}\]


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