9th Class Mathematics Surface Areas and Volumes Question Bank Surface Areas and Volumes

  • question_answer
    The height of a cone is equal to its base diameter. Then slant height of the cone is

    A) \[\sqrt{{{r}^{2}}+{{h}^{2}}}\]                     

    B) \[r\sqrt{5}\]                   

    C) \[h\sqrt{5}\]                  

    D)        \[rh\sqrt{5}\]                 

    Correct Answer: B

    Solution :

    Let radius of the cone = r \[\therefore \]Height of the cone (h) = diameter = 2r \[\therefore \]Slant height of the cone\[(l)=\sqrt{{{h}^{2}}+{{r}^{2}}}\] \[=\sqrt{{{(2r)}^{2}}+{{r}^{2}}}=\sqrt{5{{r}^{2}}}=\sqrt{5}r\]


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