A) \[616\,c{{m}^{3}}\]
B) \[600\,\,c{{m}^{3}}\]
C) \[535\,\,c{{m}^{3}}\]
D) \[716\,c{{m}^{3}}\]
Correct Answer: A
Solution :
Volume of water in the cylinder tub = Volume of the tub \[=\pi {{r}^{2}}h=\left( \frac{22}{7}\times 5\times 5\times 9.8 \right)c{{m}^{3}}=770\,c{{m}^{3}}\] Volume of the solid immersed in the tub = Volume of the hemisphere + Volume of the cone \[=\left[ \left( \frac{2}{3}\times \frac{22}{7}\times \frac{7}{2}\times \frac{7}{2}\times \frac{7}{2} \right)+\left( \frac{1}{3}\times \frac{22}{7}\times \frac{7}{2}\times \frac{7}{2}\times 5 \right) \right]c{{m}^{3}}\] \[=\left( \frac{539}{6}+\frac{385}{6} \right)\,c{{m}^{3}}=\left( \frac{924}{6} \right)c{{m}^{3}}=154c{{m}^{3}}\] Volume of water left in = Volume of the tub - Volume of solid immersed \[=(770-154)c{{m}^{3}}=616\,c{{m}^{3}}\]You need to login to perform this action.
You will be redirected in
3 sec