9th Class Mathematics Surface Areas and Volumes Question Bank Surface Areas and Volumes

  • question_answer
    The volume of two spheres are in the ratio 64 : 27. The difference of their surface areas, if the sum of their radii is 7 units, is ___.                       

    A) \[28\pi \,sq.\,\]units         

    B)  88 sq. units

    C) \[88\pi \,sq.\] units   

    D)        \[4\pi \,sq.\] units           

    Correct Answer: A

    Solution :

    Let \[{{r}_{1}}\]and \[{{r}_{2}}\]be radii of two spheres. According to question, \[\frac{\frac{4}{3}\pi r_{1}^{3}}{\frac{4}{3}\pi r_{2}^{3}}=\frac{64}{27}\Rightarrow {{\left( \frac{{{r}_{1}}}{{{r}_{2}}} \right)}^{3}}=\frac{64}{27}\Rightarrow \frac{{{r}_{1}}}{{{r}_{2}}}=\frac{4}{3}\]            ?(i) Given,   \[{{r}_{1}}+{{r}_{2}}=7\] From (i) and (ii), we get \[{{r}_{1}}=4\]units, \[{{r}_{2}}=3\]units \[\therefore \]Required difference \[=4\pi r_{1}^{2}-4\pi r_{2}^{2}\] \[=4\pi ({{4}^{2}}-{{3}^{2}})=4\pi \times 7=28\pi \,sq.\]units.


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