A) \[2\times {{10}^{-2}}N{{m}^{-1}}\]
B) \[2\times {{10}^{-4}}N{{m}^{-1}}\]
C) \[2\times {{10}^{-6}}N{{m}^{-1}}\]
D) \[2\times {{10}^{-8}}N{{m}^{-1}}\]
Correct Answer: A
Solution :
\[T=\frac{W}{\Delta A}=\frac{2\times {{10}^{-4}}}{2\times (50\times {{10}^{-4}})}=2\times {{10}^{-2}}\ N/m\]You need to login to perform this action.
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