2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Fluid Mechanics, Surface Tension & Viscosity / द्रव यांत्रिकी, भूतल तनाव और चिपचिपापन

JEE Main & Advanced Physics Fluid Mechanics, Surface Tension & Viscosity / द्रव यांत्रिकी, भूतल तनाव और चिपचिपापन Question Bank Surface Tension

  • question_answer
    The force required to separate two glass plates of area \[{{10}^{-2}}{{m}^{2}}\] with a film of water 0.05 mm thick between them, is (Surface tension of water is \[70\times {{10}^{-3}}\]N/m)              [KCET 2000; Pb. PET 2001: RPET 2002]

    A) 28 N   

    B)             14 N

    C)             50 N   

    D)             38 N

    Correct Answer: A

    Solution :

        Force required to separate the plates             \[F=\frac{2TA}{t}=\frac{2\times 70\times {{10}^{-3}}\times {{10}^{-2}}}{0.05\times {{10}^{-3}}}=28N\]


You need to login to perform this action.
You will be redirected in 3 sec spinner