A) \[a+b+c=d+e+f\]
B) \[ad+be=c+f\]
C) \[ad+be=2c+2f\]
D) \[2ad+2be=c+f\]
Correct Answer: C
Solution :
From Condition for orthogonal intersection, \[\frac{ad}{2}+\frac{be}{2}=c+f\]You need to login to perform this action.
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