A) - 4/ 3
B) 0
C) 1
D) 4/3
Correct Answer: D
Solution :
When two circles touch each other externally, then \[{{r}_{1}}+{{r}_{2}}=\sqrt{{{\left\{ 0-(-a) \right\}}^{2}}+{{\left\{ 0-(-1) \right\}}^{2}}}\] \[\Rightarrow (3+a)=\sqrt{{{a}^{2}}+1}\Rightarrow a=-4/3\]. When two circles touch each other internally, then \[{{r}_{1}}-{{r}_{2}}=\sqrt{{{\left\{ 0-(-a) \right\}}^{2}}+{{\left\{ 0-(-1) \right\}}^{2}}}\] \[\Rightarrow (3-a)=\sqrt{{{a}^{2}}+1}\Rightarrow a=4/3\].
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