JEE Main & Advanced Mathematics Circle and System of Circles Question Bank System of circles

  • question_answer
    The equation of the circle which passes through the origin, has its centre on the line \[x+y=4\]and cuts the circle \[{{x}^{2}}+{{y}^{2}}-4x+2y+4=0\]orthogonally, is

    A)            \[{{x}^{2}}+{{y}^{2}}-2x-6y=0\]                                    

    B)            \[{{x}^{2}}+{{y}^{2}}-6x-3y=0\]

    C)            \[{{x}^{2}}+{{y}^{2}}-4x-4y=0\]                                    

    D)            None of these

    Correct Answer: C

    Solution :

               Equation of circle with centre \[(-g,\ -h)\] and passing through origin is                    \[{{x}^{2}}+{{y}^{2}}+2gx+2fy=0\]                                                         ?. (i)                    and \[g+h+4=0\]                                           ?. (ii)                    Also \[-4g+2f=4\]                                          ?. (iii)                    (ii) and (iii) give g and f, which will give the desired equation \[{{x}^{2}}+{{y}^{2}}-4x-4y=0\].


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