A) \[\left( \frac{3}{2},\frac{1}{2} \right)\]
B) \[\left( \frac{1}{2},\frac{3}{2} \right)\]
C) \[\left( \frac{1}{2},\frac{1}{2} \right)\]
D) \[\left( \frac{1}{2},\ \pm \sqrt{2} \right)\]
Correct Answer: D
Solution :
Radius of the circle \[r=\frac{3}{2}\] \[\frac{1}{4}+{{k}^{2}}=\frac{9}{4}\Rightarrow k=\pm \sqrt{2}\] Hence centre is\[\left( \frac{1}{2},\ \pm \sqrt{2} \right)\].You need to login to perform this action.
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