JEE Main & Advanced Mathematics Circle and System of Circles Question Bank System of circles

  • question_answer
    The radical centre of the circles \[{{x}^{2}}+{{y}^{2}}+4x+6y=19,{{x}^{2}}+{{y}^{2}}=9\]and \[{{x}^{2}}+{{y}^{2}}-2x-2y=5\]will be

    A)            (1, 1)                                         

    B)            (-1, 1)

    C)            (1, -1)                                       

    D)            (0, 1)

    Correct Answer: A

    Solution :

               Radical axes are                    \[4x+6y=10\] or \[2x+3y=5\]                    ?.(i)                    \[2x+2y=4\] or \[x+y=2\]                           ?.(ii)                    Point of intersection of (i) and (ii) is (1, 1).


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