A) (7, - 8)
B) (- 7, 8)
C) (7, 8)
D) (- 7, - 8)
Correct Answer: B
Solution :
\[\frac{{{x}^{2}}+{{y}^{2}}+2x-4y-20}{{{x}^{2}}+{{y}^{2}}-4x+2y-44}=\frac{2}{3}\] \[\Rightarrow \] \[{{x}^{2}}+{{y}^{2}}+14x-16y+28=0\], \Centre =\[(-7,\,8)\].You need to login to perform this action.
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