A) (4, 3) and (4, -3)
B) (4, -3) and (-4, -3)
C) (-4, 3) and (4, 3)
D) (4, 3) and (3, 4)
Correct Answer: A
Solution :
\[{{x}^{2}}+{{y}^{2}}=25\] .?. (i) \[{{x}^{2}}+{{y}^{2}}-8x+7=0\] .?. (ii) From (i) and (ii), we get \[8x=7+25\]or\[x=4\] and for \[x=4\], we get \[y=\pm 3\]. Hence points of intersection are (4, 3), (4, -3).You need to login to perform this action.
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