A) 1
B) 2
C) 3
D) 0
Correct Answer: D
Solution :
Co-axial system\[{{x}^{2}}+{{y}^{2}}+2gx+c=0\], (g variable) L.H.S. = \[\Sigma ({{g}_{2}}-{{g}_{3}})({{h}^{2}}+{{k}^{2}}-c+2{{g}_{1}}h)=0\] Since \[\Sigma ({{g}_{2}}-{{g}_{3}})=0\] and \[\Sigma {{g}_{1}}({{g}_{2}}-{{g}_{3}})=0\].You need to login to perform this action.
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