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JEE Main & Advanced Mathematics Circle and System of Circles Question Bank System of circles

  • question_answer
    The radical axis of the pair of circle \[{{x}^{2}}+{{y}^{2}}=144\]and \[{{x}^{2}}+{{y}^{2}}-15x+12y=0\]is

    A)            \[15x-12y=0\]                         

    B)            \[3x-2y=12\]

    C)            \[5x-4y=48\]                           

    D)            None of these

    Correct Answer: C

    Solution :

               The radical axis of the circle \[{{S}_{1}}=0\] and \[{{S}_{2}}=0\] is \[{{S}_{1}}-{{S}_{2}}=0\]                    \[\therefore \ ({{x}^{2}}+{{y}^{2}}-144)-({{x}^{2}}+{{y}^{2}}-15x+12y)=0\]                    \[\Rightarrow 15x-12y-144=0\Rightarrow 5x-4y=48\].


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