A) Equilateral
B) Isosceles
C) Right angled
D) Right angled Isosceles
Correct Answer: D
Solution :
Let A be (0, 7, 10), B (?1, 6, 6) and C (? 4, 9, 6) Then, \[AB=\sqrt{1+1+16}=\sqrt{18}=3\sqrt{2}\] \[BC=\sqrt{9+9+0}=\sqrt{18}=3\sqrt{2}\] \[AC=\sqrt{16+4+16}=\sqrt{36}=6\] Clearly, \[A{{C}^{2}}=A{{B}^{2}}+B{{C}^{2}}\] Hence \[\Delta \] is right angled. Also, since \[AB=BC\] \ \[\Delta \] is right angled isosceles.You need to login to perform this action.
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