A) \[\frac{2}{\sqrt{10}}\]
B) \[\frac{4}{\sqrt{10}}\]
C) \[\frac{11}{\sqrt{10}}\]
D) \[\frac{22}{\sqrt{10}}\]
Correct Answer: D
Solution :
In \[\Delta ABC\], \[A\equiv (-\,3,\,0);\,\,B\equiv (4,\,\,-1)\] and \[C\equiv (5,\,\,2)\] We know that \[BC=\sqrt{{{(5-4)}^{2}}+{{(2+1)}^{2}}}\] \[=\sqrt{1+9}=\sqrt{10}\] and area of \[\Delta ABC\] \[=\frac{1}{2}[-3\,(-1-2)+4(2-0)+5\,(0+1)]=11\] Therefore, altitude \[AL=\frac{2\,\Delta ABC}{BC}=\frac{2\times 11}{\sqrt{10}}=\frac{22}{\sqrt{10}}\].You need to login to perform this action.
You will be redirected in
3 sec