A) 1
B) 0
C) - 3
D) - 2
Correct Answer: D
Solution :
For constant solution \[|A|=0\] i.e., \[\left| \,\begin{matrix} {{(\alpha +1)}^{3}} & {{(\alpha +2)}^{3}} & -{{(\alpha +3)}^{3}} \\ \alpha +1 & \alpha +2 & -(\alpha +3) \\ 1 & 1 & -1 \\ \end{matrix} \right|=0\] Þ \[6\alpha +12=0\Rightarrow \alpha =-2\].You need to login to perform this action.
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