Answer:
Here \[{{I}_{T}}=\frac{5}{3}M{{R}^{2}}\] Now diameter of sphere is an axis passing through its centre of mass. By using theorem of parallel axes, \[{{I}_{T}}={{I}_{CM}}+M{{R}^{2}}\] \[\therefore \] \[{{I}_{CM}}={{I}_{T}}-M{{R}^{2}}=\frac{5}{3}M{{R}^{2}}\] \[-M{{R}^{2}}=\frac{2}{3}M{{R}^{{}}}\]
You need to login to perform this action.
You will be redirected in
3 sec