Answer:
Here \[{{m}_{1}}={{m}_{2}}=m;\] \[\upsilon =2\upsilon \] and \[{{\upsilon }_{2}}=-\upsilon \] \[\therefore \] \[{{\upsilon }_{CM}}=\frac{{{m}_{1}}{{\upsilon }_{1}}+{{m}_{2}}{{\upsilon }_{2}}}{m+m}=\frac{m\times 2\upsilon +m(-\upsilon )}{m+m}=\frac{\upsilon }{2}\]
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