A) ? 20
B) 0
C) 5
D) Cannot be determined
Correct Answer: C
Solution :
Clearly the point (1, 2) is the centre of the given circle and infinite tangents can only be drawn on a point circle. Hence radius should be 0. \[\therefore \,\sqrt{{{1}^{2}}+{{2}^{2}}-\lambda }=0\Rightarrow \lambda =5\].You need to login to perform this action.
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