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JEE Main & Advanced Mathematics Circle and System of Circles Question Bank Tangent and normal to a circle

  • question_answer
     The square of the length of the tangent from      (3, ?4) on the circle \[{{x}^{2}}+{{y}^{2}}-4x-6y+3=0\]is [MP PET 2000]

    A)            20  

    B)            30

    C)            40  

    D)            50

    Correct Answer: C

    Solution :

               Length of tangent                    = \[\sqrt{{{3}^{2}}+{{(-4)}^{2}}-4\,(3)\,-6\,(-4)+3}\]\[=\sqrt{40}\]                             \[\therefore \] Square of length of tangent\[=40\].


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