A) \[x=0,y=0\]
B) \[({{h}^{2}}-{{r}^{2}})x-2rhy=0,x=0\]
C) \[y=0,x=4\]
D) \[({{h}^{2}}-{{r}^{2}})x+2rhy=0,x=0\]
Correct Answer: B
Solution :
The equation of tangents is \[S{{S}_{1}}={{T}^{2}}\] \[\Rightarrow {{h}^{2}}({{x}^{2}}+{{y}^{2}}-2rx-2hy+{{h}^{2}})={{(rx+hy-{{h}^{2}})}^{2}}\] \[\Rightarrow ({{h}^{2}}-{{r}^{2}}){{x}^{2}}-2rhxy=0\Rightarrow x\{({{h}^{2}}-{{r}^{2}})x-2rhy\}=0\] \[\Rightarrow x=0,\ ({{h}^{2}}-{{r}^{2}})x-2rhy=0\].
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