A) \[\sqrt{3}x+y\pm 2a=0\]
B) \[\sqrt{3}x+y\pm a=0\]
C) \[\sqrt{3}x+y\pm 4a=0\]
D) None of these
Correct Answer: A
Solution :
Equation of line parallel to the\[\sqrt{3}x+y+3=0\]is \[\sqrt{3}x+y+k=0\] .....(i) But it is a tangent to the circle\[{{x}^{2}}+{{y}^{2}}={{a}^{2}}\], then \[\left| \frac{k}{\sqrt{1+3}} \right|=a\Rightarrow k=\pm 2a\] Hence the required equation is \[\sqrt{3}x+y\pm 2a=0.\]
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