A) \[x+y+2\sqrt{2}=0\]
B) \[x+y=2\sqrt{2}\]
C) \[x+y=2\]
D) None of these
Correct Answer: B
Solution :
Equation of tangent is of the form \[x+y+c=0\] and also it obeys condition of tangency, i.e., \[\left| \frac{-2+2+c}{\sqrt{2}} \right|=\sqrt{4+4-4}\Rightarrow c=\pm \,2\sqrt{2}\] But for positive intercepts, \[c=-2\sqrt{2}\] \ The tangent is \[x+y=2\sqrt{2}\].You need to login to perform this action.
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