A) \[lg+mf-n=0\]
B) \[lg+mf+n=0\]
C) \[lg=mf-n=0\]
D) \[lg-mf+n=0\]
Correct Answer: A
Solution :
Since normal always passes through centre of circle, therefore \[(-g,\ -f)\]must lie on\[lx+my+n=0\]. Hence\[lg+mf-n=0\].You need to login to perform this action.
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