A) \[p=a\cos \alpha \]
B) \[p=a\tan \alpha \]
C) \[{{p}^{2}}={{a}^{2}}\]
D) \[p\sin \alpha =a\]
Correct Answer: C
Solution :
According to question length of perpendicular on the line from the centre of circle is equal to the radius of the circle. OM = radius of circle \[\left| \frac{-p}{\sqrt{{{\cos }^{2}}\alpha +{{\sin }^{2}}\alpha }} \right|=a\]Þ \[|-p|\ =a\Rightarrow {{p}^{2}}={{a}^{2}}\].You need to login to perform this action.
You will be redirected in
3 sec