A) \[2y=x\]
B) \[4y=3x\]
C) \[3y=4x\]
D) \[3x+4y=0\]
Correct Answer: B
Solution :
Centre (?6, 8), radius \[=\sqrt{{{6}^{2}}+{{8}^{2}}}=10\] Equation of circle \[{{x}^{2}}+{{y}^{2}}+12x-16y=0\] Equation of tangent at (0, 0) is\[3x-4y=0\] .You need to login to perform this action.
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