JEE Main & Advanced Mathematics Circle and System of Circles Question Bank Tangent and normal to a circle

  • question_answer
    If the straight line \[y=mx+c\]touches the circle \[{{x}^{2}}+{{y}^{2}}-2x-4y+3=0\]at the point (2, 3), then c =

    A)            - 3  

    B)            4

    C)            5    

    D)            ? 2

    Correct Answer: C

    Solution :

               \[y=mx+c\] is a tangent at (2, 3). Equation of tangent at (2, 3) is \[2x+3y-(x+2)-2(y+3)+3=0\]                    \[\Rightarrow 2x+3y-x-2y-2-6+3=0\]                    \[\Rightarrow x+y-5=0\Rightarrow c=5\].


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