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JEE Main & Advanced Mathematics Circle and System of Circles Question Bank Tangent and normal to a circle

  • question_answer
    The points of intersection of the line \[4x-3y-10=0\] and the circle \[{{x}^{2}}+{{y}^{2}}-2x+4y-20=0\] are               [IIT 1983]

    A)            \[(-2,-6),(4,2)\]                         

    B)            \[(2,\,6),(-4,-2)\]

    C)            \[(-2,\,6),(-4,\,2)\]                     

    D)            None of these

    Correct Answer: A

    Solution :

               Substituting \[x=\frac{3y+10}{4}\] in equation of circle, we get a quadratic in y. Solving, we get two values of y as 2 and ? 6 from which we get value of x.


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