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JEE Main & Advanced Mathematics Circle and System of Circles Question Bank Tangent and normal to a circle

  • question_answer
    The equation of the tangent to the circle \[{{x}^{2}}+{{y}^{2}}={{r}^{2}}\] at \[(a,b)\]is \[ax+by-\lambda =0\], where \[\lambda \]is

    A)            \[{{a}^{2}}\]                         

    B)            \[{{b}^{2}}\]

    C)            \[{{r}^{2}}\]                          

    D)            None of these

    Correct Answer: C

    Solution :

               Equation of tangent is\[ax+by-{{r}^{2}}=0\].


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