A) \[2x-y+1=0,\,\,x+2y-2=0\]
B) \[2x-y+1=0,\,\,x+2y+2=0\]
C) \[2x-y-1=0,\,\,x+2y-2=0\]
D) \[2x-y-1=0,\,\,x+2y+2=0\]
Correct Answer: A
Solution :
Required equations are given by \[S{{S}_{1}}={{T}^{2}}\] \[\Rightarrow ({{x}^{2}}+{{y}^{2}}-2x+4y)(1+4)={{\{y-1(x)+2(y+1)\}}^{2}}\] \[\Rightarrow 2{{x}^{2}}-2{{y}^{2}}-3x+4y+3xy-2=0\] \[\Rightarrow (2x-y+1)(x+2y-2)=0\].You need to login to perform this action.
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