A) \[3x-y=0\]
B) \[x+3y=0\]
C) \[x-3y=0\]
D) \[x+2y=0\]
Correct Answer: C
Solution :
Centre is \[(2,\ -1)\]. Therefore \[r=\left| \frac{3(2)-1}{\sqrt{10}} \right|\ =\frac{5}{\sqrt{10}}\] Now draw a perpendicular on \[x-3y=0\], we get \[r=\left| \frac{2-3(-1)}{\sqrt{10}} \right|\ =\frac{5}{\sqrt{10}}\].You need to login to perform this action.
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