A) \[y=mx+25\sqrt{1+{{m}^{2}}}\]
B) \[y=mx+5\sqrt{1+{{m}^{2}}}\]
C) \[y=mx+25\sqrt{1-{{m}^{2}}}\]
D) \[y=mx+5\sqrt{1-{{m}^{2}}}\]
Correct Answer: B
Solution :
Line \[y=mx+c\] is a tangent if \[c=\pm a\sqrt{1+{{m}^{2}}}\] \[\therefore \]\[y=mx+5\sqrt{1+{{m}^{2}}}\].You need to login to perform this action.
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