A) (0, 1)
B) (1, 0)
C) (1, 1)
D) (?1, ?1)
Correct Answer: B
Solution :
Curve \[x+y={{e}^{xy}}\] Differentiating with respect to x \[1+\frac{dy}{dx}={{e}^{xy}}\left( y+x\frac{dy}{dx} \right)\] or \[\frac{dy}{dx}=\frac{y{{e}^{xy}}-1}{1-x{{e}^{xy}}}\] \[\frac{dy}{dx}=\infty \Rightarrow 1-x{{e}^{xy}}=0\Rightarrow 1-x(x+y)=0\] This hold for \[x=1\], \[y=0\].You need to login to perform this action.
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