A) (1, 1)
B) (?1, 1)
C) (\[\sqrt{3}\], 0)
D) (3, ?3)
Correct Answer: A
Solution :
Given curve \[{{x}^{2}}=3-2y\] ...(i) Differentiate w.r.t. x, \[2x=0-2\frac{dy}{dx}\]\[\Rightarrow \]\[\frac{dy}{dx}=-x\] Slope of the tangent of the curve \[=-x\] From the given line, slope \[=-1\],\[\therefore x=1\] and from equation (i), \[y=1\]. \[\therefore \]Co-ordinate of the point is (1, 1).You need to login to perform this action.
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