A) \[y=1\]
B) \[x=1\]
C) \[y=x\]
D) \[y-1=\frac{-2}{\pi }(x-1)\]
Correct Answer: B
Solution :
\[y=\sin \frac{\pi x}{2}\] Þ \[\frac{dy}{dx}=\frac{\pi }{2}\cos \frac{\pi }{2}x\]Þ \[{{\left( \frac{dy}{dx} \right)}_{(1,\,\,1)}}=0\] \ Equation of normal is \[y-1=\frac{1}{0}(x-1)\] Þ\[x=1\].You need to login to perform this action.
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