A) \[\pi /4\]
B) \[\pi /3\]
C) \[\pi /2\]
D) \[\pi \]
Correct Answer: C
Solution :
\[y={{x}^{2}}\] Þ \[{{\left( \frac{dy}{dx} \right)}_{(1,\,1)}}={{m}_{1}}=2x=2\] \[6y=7-{{x}^{3}}\Rightarrow 6\,.\,\frac{dy}{dx}=-3{{x}^{2}}\] Þ\[{{\left( \frac{dy}{dx} \right)}_{(1,\,1)}}={{m}_{2}}=-\frac{1}{2}\] Clearly \[{{m}_{1}}{{m}_{2}}=-1,\] therefore angle of intersection is \[\frac{\pi }{2}\].You need to login to perform this action.
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